1869 United States Senate election in Massachusetts
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(Redirected from United States Senate election in Massachusetts, 1869)
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40 Members of the Massachusetts Senate 231 Members of the Massachusetts House Majority vote of each house needed to win | |||||||||||||||||||||||
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The 1869 United States Senate election in Massachusetts was held on January 19, 1869. Incumbent Charles Sumner was re-elected to a fourth term in office.
At the time, Massachusetts elected United States senators by a majority vote of each separate house of the Massachusetts General Court: the House and the Senate.
Background
[edit]In the 1868 state legislative elections, Republicans maintained an overwhelming majority in both houses. Only 20 Democratic Representatives and two Democratic Senators were elected. This ensured Sumner's re-election in the January session, though there was some speculation that Sumner would vacate his seat to accept a Cabinet appointment in the newly elected Grant administration.[1]
Election
[edit]Election in the House
[edit]Party | Candidate | Votes | % | |
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Republican | Charles Sumner (incumbent) | 216 | 93.51% | |
Democratic | Josiah G. Abbott | 14 | 6.06% | |
Republican | Nathaniel P. Banks | 1 | 0.43% | |
Total votes | 231 | 100.00% |
Election in the Senate
[edit]Party | Candidate | Votes | % | |
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Republican | Charles Sumner (incumbent) | 37 | 92.5% | |
Democratic | Josiah G. Abbott | 2 | 5% | |
None | No vote | 1 | 2.5% | |
Total votes | 40 | 100.00% |