1836 New Hampshire gubernatorial election
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The 1836 New Hampshire gubernatorial election was held on 8 March 1836 in order to elect the Governor of New Hampshire. Former Democratic United States Senator from New Hampshire Isaac Hill defeated Whig nominee Joseph Healey and former Federalist Attorney General of New Hampshire George Sullivan.[1]
General election
[edit]On election day, 8 March 1836, Democratic nominee Isaac Hill won the election by a margin of 22,338 votes against his foremost opponent Whig nominee Joseph Healey, thereby retaining Democratic control over the office of Governor. Hill was sworn in as the 16th Governor of New Hampshire on 2 June 1836.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Isaac Hill | 24,904 | 81.22 | |
| Whig | Joseph Healey | 2,566 | 8.37 | |
| George Sullivan | 2,230 | 7.27 | ||
| Scattering | 961 | 3.14 | ||
| Total votes | 30,661 | 100.00 | ||
| Democratic hold | ||||
References
[edit]- ^ "Isaac Hill". National Governors Association. Retrieved 2 April 2024.
- ^ "NH Governor". ourcampaigns.com. 3 June 2005. Retrieved 2 April 2024.
Categories:
- 1836 New Hampshire elections
- New Hampshire gubernatorial elections
- 1836 United States gubernatorial elections
- March 1836 events
- 1836 in New Hampshire
- 1830s in New Hampshire
- 1830s New Hampshire elections
- 1836 elections
- 1836 elections in North America
- 1836 elections in the United States
- United States gubernatorial elections in the 1830s
- Government of New Hampshire