1846 Iowa gubernatorial election

1846 Iowa gubernatorial election
	County results ; Briggs: 50-60% 60-70% 70-80% 80-90%; McKnight: 50-60% 60-70%; No Data/Votes:
Governor before election; James Clarke (Territorial); Whig	Elected Governor ; Ansel Briggs; Democratic

The 1846 Iowa gubernatorial election was held on 26 October 1846 in order to elect the first Governor of Iowa upon Iowa acquiring statehood on 28 December 1846. Democratic nominee Ansel Briggs defeated Whig nominee Thomas McKnight.^[1]

General election

On election day, 26 October 1846, Democratic nominee Ansel Briggs won the election by a margin of 247 votes against his opponent Whig nominee Thomas McKnight, thereby gaining Democratic control over the new office of Governor. Briggs was sworn in as the 1st Governor of the new state of Iowa on 28 December 1846.^[2]

Results

Iowa gubernatorial election, 1846
Party		Candidate	Votes	%
	Democratic	Ansel Briggs	7,626	50.82
	Whig	Thomas McKnight	7,379	49.18
Total votes			15,005	100.00
	Democratic gain from Whig

References

^ "Ansel Briggs". National Governors Association. Retrieved July 14, 2023.
^ "IA Governor". ourcampaigns.com. March 4, 2005. Retrieved July 14, 2023.

[nga-briggs-1] "Ansel Briggs". National Governors Association. Retrieved July 14, 2023.

[GBN-2] "IA Governor". ourcampaigns.com. March 4, 2005. Retrieved July 14, 2023.

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