1892 Missouri lieutenant gubernatorial election
Appearance
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Elections in Missouri |
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The 1892 Missouri lieutenant gubernatorial election was held on 8 November 1892 in order to elect the lieutenant governor of Missouri. Democratic nominee John Baptiste O'Meara defeated Republican nominee Rudolph W. Mueller, People's nominee George W. Williams and Prohibition nominee William S. Crouch.[1]
General election
[edit]On election day, 8 November 1892, Democratic nominee John Baptiste O'Meara won the election by a margin of 31,816 votes against his foremost opponent Republican nominee Rudolph W. Mueller, thereby retaining Democratic control over the office of lieutenant governor. O'Meara was sworn in as the 22nd lieutenant governor of Missouri on 9 January 1893.[2]
Results
[edit]Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic | John Baptiste O'Meara | 263,000 | 48.73 | |
Republican | Rudolph W. Mueller | 231,184 | 42.84 | |
Populist | George W. Williams | 41,293 | 7.65 | |
Prohibition | William S. Crouch | 4,204 | 0.78 | |
Total votes | 539,681 | 100.00 | ||
Democratic hold |
See also
[edit]References
[edit]- ^ "1892 Lt. Gubernatorial General Election Results - Missouri". uselectionatlas.org. 8 July 2016. Retrieved 22 October 2024.
- ^ "MO Lt. Governor". ourcampaigns.com. 17 December 2007. Retrieved 22 October 2024.
Categories:
- 1892 Missouri elections
- 1892 in Missouri
- Missouri lieutenant gubernatorial elections
- 1892 elections
- November 1892 events
- 1892 elections in North America
- 1892 elections in the United States
- 1890s elections
- 1890s elections in North America
- 1890s elections in the United States
- 1890s Missouri elections
- 1890s in Missouri
- Government of Missouri