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1957 U.S. National Championships – Women's singles

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Women's singles
1957 U.S. National Championships
Final
ChampionUnited States Althea Gibson
Runner-upUnited States Louise Brough[1]
Score6–3, 6–2
Details
Seeds8
Events
Singles men women
Doubles men women
← 1956 · U.S. National Championships · 1958 →

Althea Gibson defeated Louise Brough in the final, 6–3, 6–2 to win the women's singles tennis title at the 1957 U.S. National Championships.[1] Gibson won the tournament without losing a set.[2]

Seeds

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The seeded players are listed below. Althea Gibson is the champion; others show in brackets the round in which they were eliminated.

  1. United States Althea Gibson (champion)
  2. United States Louise Brough (finalist)
  3. United States Dorothy Knode (semifinals)
  4. United Kingdom Shirley Bloomer (quarterfinals)
  5. United States Darlene Hard (semifinals)
  6. United Kingdom Christine Truman (third round)
  7. United Kingdom Ann Haydon (quarterfinals)
  8. Australia Mary Hawton (quarterfinals)

Draw

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Key

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Final eight

[edit]
Quarterfinals Semifinals Finals
               
1 United States Althea Gibson 6 6
8 Australia Mary Hawton 2 2
1 United States Althea Gibson 6 6
3 United States Dorothy Knode 2 2
3 United States Dorothy Knode 6 6
United States Lois Felix 2 1
1 United States Althea Gibson 6 6
2 United States Louise Brough 3 2
2 United States Louise Brough 7 6
7 United Kingdom Ann Haydon 5 2
2 United States Louise Brough 6 6
5 United States Darlene Hard 1 4
4 United Kingdom Shirley Bloomer 0 1
5 United States Darlene Hard 6 6

References

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  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0-942257-70-0.
  2. ^ "Results". World Tennis. Vol. 5, no. 5. New York. October 1957. p. 87. Retrieved 30 September 2024.
Preceded by Grand Slam women's singles Succeeded by