Wikipedia:Reference desk/Archives/Mathematics/2023 March 8

Welcome to the Wikipedia Mathematics Reference Desk Archives
The page you are currently viewing is a transcluded archive page. While you can leave answers for any questions shown below, please ask new questions on one of the current reference desk pages.

March 8

Converting UTM coordinates to latitude and longitude

I figure I should start with the article I'm referencing. In particular, I'm looking at the last set of formulae in this article, to convert UTM to lat-long coordinates:

Universal_Transverse_Mercator_coordinate_system#From_UTM_coordinates_(E,_N,_Zone,_Hemi)_to_latitude,_longitude_(φ,_λ)

The formula has a few variables that are a mystery to me, particularly "j" and beta j. Can a math wizard walk me through this calculation? I'd like to create a script to generate lat-long coordinates from a pair of UTM coordinates, all within 17N. - Floydian ^τ _¢ 17:58, 8 March 2023 (UTC)

The variable $j$ in these formulas is a bound variable. It is bound by the summations, written with a capital Greek letter $\textstyle \sum .$ The notation

$\sum _{j=1}^{3}2j\beta _{j}\cos(2j\xi )\cosh(2j\eta )$

is convenient shorthand for

$2\beta _{1}\cos(2\xi )\cosh(2\eta )+4\beta _{2}\cos(4\xi )\cosh(4\eta )+6\beta _{3}\cos(6\xi )\cosh(6\eta ).$

The three coefficients $\beta _{1},$ $\beta _{2}$ and $\beta _{3}$ are defined in the beginning of the section Simplified formulae.  --Lambiam 18:28, 8 March 2023 (UTC)

In the simplified formulae, no info is provided for the value of f. I hope its not too much to ask, but say I had a Northing of 5,100,000m and an Easting of 500,000m in zone 17N... could you walk me through the calculations? - Floydian ^τ _¢ 14:56, 10 March 2023 (UTC)

What do you mean? Universal Transverse Mercator coordinate system § Simplified formulae directly quotes the value of f for WGS 84. Anyhow, you might be interested in Charles Karney's paper or software. –jacobolus (t) 17:20, 10 March 2023 (UTC)

It is already all laid out in elementary steps that is almost a script. I think it is not going to help you if we write out the steps like,

Step 1: Calculate $\xi ={\frac {N-N_{0}}{k_{0}A}}.$

Step 2: Calculate $\eta ={\frac {E-E_{0}}{k_{0}A}}.$

Step 3: Calculate $\xi '=\xi -\sum _{j=1}^{3}\beta _{j}\sin \left(2j\xi \right)\cosh \left(2j\eta \right).$

...

A problem we have with "walking you through the calculations" is that we don't know how we are supposed to make it simpler.  --Lambiam 17:44, 10 March 2023 (UTC)